-2000+1300x+1500x^2=0

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Solution for -2000+1300x+1500x^2=0 equation:



-2000+1300x+1500x^2=0
a = 1500; b = 1300; c = -2000;
Δ = b2-4ac
Δ = 13002-4·1500·(-2000)
Δ = 13690000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13690000}=3700$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1300)-3700}{2*1500}=\frac{-5000}{3000} =-1+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1300)+3700}{2*1500}=\frac{2400}{3000} =4/5 $

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